Engineering Statics


The brass knob shown is to be nickel plated to a specified thickness, but the surface area is needed to calculate the amount of plating solution. Determine the total surface area of the solid brass knob shown.

We make the drawing that indicates the bottom half of the sphere A<sub>2</sub> and 
the top half which goes from the 400 mm level to the 600 mm level.
The area dA is equation to the heigth (y<sub>1</sub>-y<sub>2</sub>) times 
the width, dx.
The upper lime has the equation y = mx and the lower curve has the equation 
y=kx<sup>3</sup>.  These are substituted into the equation for the two 
values of y.
The constants m and k can be found from the values a and b given on the 
diagram.  The slope of the line, m, is b/a.  For the curve when y=b 
x=a, hence the equation becomes b=ka<sup)3</sup>.
The values for m and k are substituted into the expression for dA.
Integrating with limits on x from 0 to a:
The integration is performed.
The upper and lower limits are substituted in.
The centroid is defined as the first moment of the area divided by the area.
Notice that the integral is the integral for finding the area with each 
terms permultiplied by x.  We are adding up all the first moments of the 
infitessimal areas dA.  The term (4/ab) is the reciprocal of the area.  In 
other words we are dividing by the area to immediately get the centroid.
Simplification sets up the integral.
Substituting limits and cancelling:
Simplifying gives the location of the centroid in the x direction.
The definition of the centroid in the y-direction is given.
The same value for dA is substituted as was in the integral for the centroid 
in the x-direction.  Note the term (y<sub>1</sub>+y<sub>2</sub>)/2.  This term 
is the distance from the x axis to the centroid of the area dA.  This the average 
of the distance to the top and the distance to the bottom of the area dA.
The expressions arae simplified.
Values for y<sub>1</sub> and y<sub>2</sub> are substituted.  The term 
2/ab is the reciprocal of the area A, divided by 2.  The 2 appears from 
the denominator for the average of the vertical distances.
The expression is integrated.
Limits of integration are substituted.
The centroid in the y direction is found.